验证码识别请求偶尔失败很正常——队列打满、网络抖动、服务端过载都可能导致一次出错。关键是分清哪些错误值得重试、哪些重试也没用。本文贯穿一套统一思路:有限次数重试、带抖动的指数退避,以及 API 持续异常时自动熔断。
哪些错误该重试,哪些不该重试
先把错误分类,再动手写重试代码,能省下大量无意义的调试时间:
| 错误 | 是否重试 | 原因 |
|---|---|---|
ERROR_NO_SLOT_AVAILABLE |
是 | 队列临时打满 |
| HTTP 429 | 是 | 触发限流 |
| HTTP 500/502/503 | 是 | 服务端临时故障 |
| 连接超时 | 是 | 网络抖动 |
CAPCHA_NOT_READY |
继续轮询 | 任务仍在处理中 |
ERROR_WRONG_USER_KEY |
否 | 配置错误,需修正 API Key |
ERROR_KEY_DOES_NOT_EXIST |
否 | Key 无效 |
ERROR_ZERO_BALANCE |
否 | 需先充值余额 |
ERROR_CAPTCHA_UNSOLVABLE |
重新提交 | 用新参数发起全新任务 |
遇到双 11 这类流量高峰、国际出口带宽紧张的时段,连接超时和 HTTP 5xx 会更频繁——这正是重试逻辑体现价值的场景。
基础重试:指数退避加抖动
下面这段代码把"该不该重试"的判断和退避等待封装到一起,提交任务时直接调用即可:
import requests
import time
import random
API_KEY = "YOUR_API_KEY"
BASE_URL = "https://ocr.captchaai.com"
# Errors that should NOT be retried
PERMANENT_ERRORS = {
"ERROR_WRONG_USER_KEY",
"ERROR_KEY_DOES_NOT_EXIST",
"ERROR_ZERO_BALANCE",
"ERROR_BAD_PARAMETERS",
"ERROR_WRONG_CAPTCHA_ID",
}
# Errors that should be retried
TRANSIENT_ERRORS = {
"ERROR_NO_SLOT_AVAILABLE",
"ERROR_TOO_MUCH_REQUESTS",
}
def submit_with_retry(method, max_retries=5, **params):
"""Submit task with retry on transient errors."""
data = {"key": API_KEY, "method": method, "json": 1}
data.update(params)
for attempt in range(max_retries):
try:
resp = requests.post(
f"{BASE_URL}/in.php", data=data, timeout=30,
)
# HTTP-level errors
if resp.status_code in (429, 500, 502, 503):
wait = _backoff(attempt)
print(f"HTTP {resp.status_code}, retry in {wait:.1f}s")
time.sleep(wait)
continue
result = resp.json()
# Permanent errors — don't retry
if result.get("request") in PERMANENT_ERRORS:
raise RuntimeError(f"Permanent error: {result['request']}")
# Transient errors — retry
if result.get("request") in TRANSIENT_ERRORS:
wait = _backoff(attempt)
print(f"{result['request']}, retry in {wait:.1f}s")
time.sleep(wait)
continue
# Success
if result.get("status") == 1:
return result["request"]
# Unknown error
raise RuntimeError(f"Unknown error: {result.get('request')}")
except requests.ConnectionError:
wait = _backoff(attempt)
print(f"Connection error, retry in {wait:.1f}s")
time.sleep(wait)
except requests.Timeout:
wait = _backoff(attempt)
print(f"Timeout, retry in {wait:.1f}s")
time.sleep(wait)
raise RuntimeError(f"Failed after {max_retries} retries")
def _backoff(attempt, base=2, max_wait=60):
"""Exponential backoff with jitter."""
wait = min(base ** attempt, max_wait)
jitter = random.uniform(0, wait * 0.5)
return wait + jitter
PERMANENT_ERRORS 和 TRANSIENT_ERRORS 判断顺序不能反。_backoff 里的 jitter 不是装饰——没有随机量,大量客户端会同一秒集体重试,反而更容易触发限流。
轮询阶段怎么重试
提交任务只是第一步,拿到 token 要靠轮询 res.php。轮询逻辑和提交阶段类似,但要多维护一个"连续错误计数",避免偶发的单次错误就直接判定失败:
def poll_with_retry(task_id, timeout=120, max_poll_errors=3):
"""Poll for result with error retry."""
start = time.time()
consecutive_errors = 0
while time.time() - start < timeout:
time.sleep(5)
try:
resp = requests.get(f"{BASE_URL}/res.php", params={
"key": API_KEY, "action": "get",
"id": task_id, "json": 1,
}, timeout=15)
if resp.status_code in (429, 500, 502, 503):
consecutive_errors += 1
if consecutive_errors >= max_poll_errors:
raise RuntimeError("Too many poll errors")
time.sleep(_backoff(consecutive_errors))
continue
data = resp.json()
consecutive_errors = 0 # Reset on success
if data["request"] == "CAPCHA_NOT_READY":
continue
if data["request"] in PERMANENT_ERRORS:
raise RuntimeError(f"Solve error: {data['request']}")
return data["request"]
except (requests.ConnectionError, requests.Timeout):
consecutive_errors += 1
if consecutive_errors >= max_poll_errors:
raise RuntimeError("Too many poll connection errors")
time.sleep(_backoff(consecutive_errors))
raise TimeoutError(f"Task {task_id} timeout after {timeout}s")
consecutive_errors 在每次成功响应后会重置为 0——达标条件是"连续"失败,不是累计失败次数,改错了会让脚本在网络稍有波动时就提前判定超时。
打包成生产级 Solver 类
把提交和轮询合并进一个类,再加上统计信息,方便接入正式的自动化流程:
class RetrySolver:
"""Production-grade solver with comprehensive retry logic."""
def __init__(self, api_key, max_submit_retries=5, max_poll_retries=3,
poll_timeout=120):
self.api_key = api_key
self.base = "https://ocr.captchaai.com"
self.max_submit_retries = max_submit_retries
self.max_poll_retries = max_poll_retries
self.poll_timeout = poll_timeout
self.stats = {
"total": 0, "success": 0, "retry": 0,
"permanent_error": 0, "timeout": 0,
}
def solve(self, method, **params):
self.stats["total"] += 1
# Submit with retry
task_id = self._submit(method, **params)
# Poll with retry
try:
token = self._poll(task_id)
self.stats["success"] += 1
return token
except TimeoutError:
self.stats["timeout"] += 1
raise
def _submit(self, method, **params):
data = {"key": self.api_key, "method": method, "json": 1}
data.update(params)
for attempt in range(self.max_submit_retries):
try:
resp = requests.post(
f"{self.base}/in.php", data=data, timeout=30,
)
if resp.status_code in (429, 500, 502, 503):
self.stats["retry"] += 1
time.sleep(_backoff(attempt))
continue
result = resp.json()
if result.get("request") in PERMANENT_ERRORS:
self.stats["permanent_error"] += 1
raise RuntimeError(f"Permanent: {result['request']}")
if result.get("request") in TRANSIENT_ERRORS:
self.stats["retry"] += 1
time.sleep(_backoff(attempt))
continue
if result.get("status") == 1:
return result["request"]
except (requests.ConnectionError, requests.Timeout):
self.stats["retry"] += 1
time.sleep(_backoff(attempt))
raise RuntimeError("Submit failed after retries")
def _poll(self, task_id):
start = time.time()
errors = 0
while time.time() - start < self.poll_timeout:
time.sleep(5)
try:
resp = requests.get(f"{self.base}/res.php", params={
"key": self.api_key, "action": "get",
"id": task_id, "json": 1,
}, timeout=15)
if resp.status_code in (429, 500, 502, 503):
errors += 1
if errors >= self.max_poll_retries:
raise RuntimeError("Poll errors exceeded limit")
time.sleep(_backoff(errors))
continue
data = resp.json()
errors = 0
if data["request"] == "CAPCHA_NOT_READY":
continue
if data.get("status") == 1:
return data["request"]
raise RuntimeError(f"Solve error: {data['request']}")
except (requests.ConnectionError, requests.Timeout):
errors += 1
if errors >= self.max_poll_retries:
raise
raise TimeoutError("Poll timeout")
def get_stats(self):
return self.stats
# Usage
solver = RetrySolver("YOUR_API_KEY")
token = solver.solve(
"userrecaptcha",
googlekey="SITE_KEY",
pageurl="https://example.com",
)
print(solver.get_stats())
get_stats() 排查问题很有用:retry 偏高但 success 正常说明只是网络不稳;permanent_error 持续增长多半是配置出了问题,再重试也没用。
用熔断器防止无意义的持续请求
API 连续多次失败时,继续按原频率重试只会浪费配额、拖慢流水线。熔断器的作用是:失败次数达到阈值就直接拒绝新请求,等冷却时间过后再尝试放行:
class CircuitBreaker:
"""Stop requests when the service appears down."""
def __init__(self, failure_threshold=5, recovery_time=60):
self.failure_threshold = failure_threshold
self.recovery_time = recovery_time
self.failures = 0
self.last_failure = 0
self.state = "closed" # closed=normal, open=blocking
def can_proceed(self):
if self.state == "closed":
return True
# Check if recovery time has passed
if time.time() - self.last_failure > self.recovery_time:
self.state = "half-open"
return True
return False
def record_success(self):
self.failures = 0
self.state = "closed"
def record_failure(self):
self.failures += 1
self.last_failure = time.time()
if self.failures >= self.failure_threshold:
self.state = "open"
print(f"Circuit OPEN — pausing for {self.recovery_time}s")
# Integrate with solver
breaker = CircuitBreaker(failure_threshold=5, recovery_time=60)
def solve_with_breaker(method, **params):
if not breaker.can_proceed():
raise RuntimeError("Circuit open — API appears unavailable")
try:
token = solver.solve(method, **params)
breaker.record_success()
return token
except RuntimeError:
breaker.record_failure()
raise
state 有三种取值:closed(正常放行)、open(拒绝请求)、half-open(冷却后试探放行一次)。这能让整个集群一起降速,而不是几百个并发请求同时死磕一个不可用的接口。
常见故障排查
| 问题 | 原因 | 处理方式 |
|---|---|---|
| 把永久性错误也重试了 | 没有按错误类型过滤 | 核对请求结果是否在 PERMANENT_ERRORS 集合中 |
| 重试次数没有上限 | 缺少 max_retries |
务必显式设置重试上限 |
| 退避间隔涨得太慢 | 用了固定延迟 | 改用带抖动的指数退避 |
| 重试多次结果都一样 | 问题本身不是暂时性的 | 检查 API Key、账户余额和请求参数是否正确 |
常见问题
提交和轮询分别应该重试几次?
提交阶段 3–5 次,轮询阶段连续错误 2–3 次。超过这个次数收益很有限——问题往往已经不是暂时性的了。
熔断器(Circuit Breaker)打开之后大概多久会恢复?
取决于 recovery_time。示例代码设为 60 秒:熔断器打开后等待 60 秒会自动切换到"半开"状态并放行下一次请求,成功就重新闭合,失败就再次打开。
轮询间隔为什么设置成 5 秒,可以更短吗?
5 秒是折中值——太短容易撞上限流,太长又拖慢整体识别速度。可按实际观察调整,但不建议低于 2–3 秒。
ERROR_CAPTCHA_UNSOLVABLE 要不要重试?
可以,但别重试同一个任务 ID——相同任务不会给出不同结果。正确做法是用新参数重新提交一个全新任务,对应上面表格里"重新提交"这一行。
相关指南
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